3.10.97 \(\int x^m (c x^2)^p (a+b x)^n \, dx\) [997]

Optimal. Leaf size=63 \[ \frac {x^{1+m} \left (c x^2\right )^p (a+b x)^n \left (1+\frac {b x}{a}\right )^{-n} \, _2F_1\left (-n,1+m+2 p;2+m+2 p;-\frac {b x}{a}\right )}{1+m+2 p} \]

[Out]

x^(1+m)*(c*x^2)^p*(b*x+a)^n*hypergeom([-n, 1+m+2*p],[2+m+2*p],-b*x/a)/(1+m+2*p)/((1+b*x/a)^n)

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Rubi [A]
time = 0.02, antiderivative size = 63, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {15, 68, 66} \begin {gather*} \frac {x^{m+1} \left (c x^2\right )^p (a+b x)^n \left (\frac {b x}{a}+1\right )^{-n} \, _2F_1\left (-n,m+2 p+1;m+2 p+2;-\frac {b x}{a}\right )}{m+2 p+1} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^m*(c*x^2)^p*(a + b*x)^n,x]

[Out]

(x^(1 + m)*(c*x^2)^p*(a + b*x)^n*Hypergeometric2F1[-n, 1 + m + 2*p, 2 + m + 2*p, -((b*x)/a)])/((1 + m + 2*p)*(
1 + (b*x)/a)^n)

Rule 15

Int[(u_.)*((a_.)*(x_)^(n_))^(m_), x_Symbol] :> Dist[a^IntPart[m]*((a*x^n)^FracPart[m]/x^(n*FracPart[m])), Int[
u*x^(m*n), x], x] /; FreeQ[{a, m, n}, x] &&  !IntegerQ[m]

Rule 66

Int[((b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[c^n*((b*x)^(m + 1)/(b*(m + 1)))*Hypergeometr
ic2F1[-n, m + 1, m + 2, (-d)*(x/c)], x] /; FreeQ[{b, c, d, m, n}, x] &&  !IntegerQ[m] && (IntegerQ[n] || (GtQ[
c, 0] &&  !(EqQ[n, -2^(-1)] && EqQ[c^2 - d^2, 0] && GtQ[-d/(b*c), 0])))

Rule 68

Int[((b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_), x_Symbol] :> Dist[c^IntPart[n]*((c + d*x)^FracPart[n]/(1 + d*(
x/c))^FracPart[n]), Int[(b*x)^m*(1 + d*(x/c))^n, x], x] /; FreeQ[{b, c, d, m, n}, x] &&  !IntegerQ[m] &&  !Int
egerQ[n] &&  !GtQ[c, 0] &&  !GtQ[-d/(b*c), 0] && ((RationalQ[m] &&  !(EqQ[n, -2^(-1)] && EqQ[c^2 - d^2, 0])) |
|  !RationalQ[n])

Rubi steps

\begin {align*} \int x^m \left (c x^2\right )^p (a+b x)^n \, dx &=\left (x^{-2 p} \left (c x^2\right )^p\right ) \int x^{m+2 p} (a+b x)^n \, dx\\ &=\left (x^{-2 p} \left (c x^2\right )^p (a+b x)^n \left (1+\frac {b x}{a}\right )^{-n}\right ) \int x^{m+2 p} \left (1+\frac {b x}{a}\right )^n \, dx\\ &=\frac {x^{1+m} \left (c x^2\right )^p (a+b x)^n \left (1+\frac {b x}{a}\right )^{-n} \, _2F_1\left (-n,1+m+2 p;2+m+2 p;-\frac {b x}{a}\right )}{1+m+2 p}\\ \end {align*}

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Mathematica [A]
time = 0.03, size = 63, normalized size = 1.00 \begin {gather*} \frac {x^{1+m} \left (c x^2\right )^p (a+b x)^n \left (1+\frac {b x}{a}\right )^{-n} \, _2F_1\left (-n,1+m+2 p;2+m+2 p;-\frac {b x}{a}\right )}{1+m+2 p} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^m*(c*x^2)^p*(a + b*x)^n,x]

[Out]

(x^(1 + m)*(c*x^2)^p*(a + b*x)^n*Hypergeometric2F1[-n, 1 + m + 2*p, 2 + m + 2*p, -((b*x)/a)])/((1 + m + 2*p)*(
1 + (b*x)/a)^n)

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Maple [F]
time = 0.06, size = 0, normalized size = 0.00 \[\int x^{m} \left (c \,x^{2}\right )^{p} \left (b x +a \right )^{n}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^m*(c*x^2)^p*(b*x+a)^n,x)

[Out]

int(x^m*(c*x^2)^p*(b*x+a)^n,x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^m*(c*x^2)^p*(b*x+a)^n,x, algorithm="maxima")

[Out]

integrate((c*x^2)^p*(b*x + a)^n*x^m, x)

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^m*(c*x^2)^p*(b*x+a)^n,x, algorithm="fricas")

[Out]

integral((c*x^2)^p*(b*x + a)^n*x^m, x)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x^{m} \left (c x^{2}\right )^{p} \left (a + b x\right )^{n}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**m*(c*x**2)**p*(b*x+a)**n,x)

[Out]

Integral(x**m*(c*x**2)**p*(a + b*x)**n, x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^m*(c*x^2)^p*(b*x+a)^n,x, algorithm="giac")

[Out]

integrate((c*x^2)^p*(b*x + a)^n*x^m, x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int x^m\,{\left (c\,x^2\right )}^p\,{\left (a+b\,x\right )}^n \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^m*(c*x^2)^p*(a + b*x)^n,x)

[Out]

int(x^m*(c*x^2)^p*(a + b*x)^n, x)

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